Get started today!

Good to have you back!
If you've signed in to StudyBlue with Facebook in the past, please do that again.

- StudyBlue
- North-carolina
- University of North Carolina-Wilmington
- Mathematics
- Mathematics 261
- Wang
- REVIEW # 3

Kendall L.

(1/n+1)x^{n+1} +C

ln[x]+c

Advertisement
)

[S]a f(x)dx=

a[S]fxdx

[S] K dx=

*where K is a constant*

Kx + C

[S] K f(x) dx=

[S] a^{x} dx =

= (1/lna) * a^{x} + C

[S] (f(x))^{n} * f'(x) dx=

= [f(x)]^{n+1} * 1/(n+1) +C

[S] r (w)^{n}dx

= r/w' * (1/n+1)w^{n+1} + C

[S] r*e^{f(x)}dx=

r/f'(x) * e^{f(x)} +C

[S] [g(x)+-f(x)]dx

[S]g(x)dx +- [S]f(x)dx

[S] dx

= x + c

f'(x)=

f(x)= u/v

f'(x)=?

= ( *u*' *v* + *v*' *u)/ (v*^{2})

x'=

1

Advertisement

k'=

0

y= (f(x))^{n}

y'=?

y'= n(f(x))^{n-1} f'(x)

f(x)= a^{x}

f'(x0)=?

= a^{x} ln(a) x

f(x)= logf(x)

f'(x)=

(1/ln(a)) (1/fx) f'(x)

"StudyBlue is great for studying. I love the study guides, flashcards and quizzes. So extremely helpful for all of my classes!"

Alice , Arizona State University"I'm a student using StudyBlue, and I can 100% say that it helps me so much. Study materials for almost every subject in school are available in StudyBlue. It is so helpful for my education!"

Tim , University of Florida"StudyBlue provides way more features than other studying apps, and thus allows me to learn very quickly!Â I actually feel much more comfortable taking my exams after I study with this app. It's amazing!"

Jennifer , Rutgers University"I love flashcards but carrying around physical flashcards is cumbersome and simply outdated. StudyBlue is exactly what I was looking for!"

Justin , LSU