# Test 2 Review

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- Florida
- Valencia Community College
- Calculus
- Calculus 2311
- Boustique
- Test 2 Review

**Created:**2014-03-16

**Last Modified:**2014-03-16

^{2}"

^{2}x = 1/(cos

^{2}x)

^{2}(x)

_{1}=m(x-x

_{1})

*f*is continuous on a closed interval [a,b], then

*f*attains an absolute maximum value

*f(c)*and an absolute minimum value

*f(d)*at some numbers

*c*and

*d*in [a,b],

(1) continuous on [a,b]

(2) differentiable on (a,b,

then there exists a # c in (a,b) such that

f'(c)=

__f(b) - f(a)__

b - a

(a) If f'(c) = 0 and f''(c)>0, then f has a local minimum at c.

(b) If f'(c) = 0 and f''(c)<0, then f has a local maximum at c.

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